Base | Representation |
---|---|
bin | 110000000001001110… |
… | …1000111101110000011 |
3 | 100212011122020020220110 |
4 | 1200002131013232003 |
5 | 3142142310401311 |
6 | 115212312042403 |
7 | 10310263652211 |
oct | 1400235075603 |
9 | 325148206813 |
10 | 103120403331 |
11 | 3a807863330 |
12 | 17b9a993403 |
13 | 995512c64a |
14 | 4dc3649cb1 |
15 | 2a381638a6 |
hex | 1802747b83 |
103120403331 has 64 divisors (see below), whose sum is σ = 165441576960. Its totient is φ = 56396736000.
The previous prime is 103120403327. The next prime is 103120403339. The reversal of 103120403331 is 133304021301.
It is not a de Polignac number, because 103120403331 - 22 = 103120403327 is a prime.
It is a super-2 number, since 2×1031204033312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103120403298 and 103120403307.
It is not an unprimeable number, because it can be changed into a prime (103120403339) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3460626 + ... + 3490296.
It is an arithmetic number, because the mean of its divisors is an integer number (2585024640).
Almost surely, 2103120403331 is an apocalyptic number.
103120403331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
103120403331 is a deficient number, since it is larger than the sum of its proper divisors (62321173629).
103120403331 is a wasteful number, since it uses less digits than its factorization.
103120403331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29968.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 103120403331 its reverse (133304021301), we get a palindrome (236424424632).
The spelling of 103120403331 in words is "one hundred three billion, one hundred twenty million, four hundred three thousand, three hundred thirty-one".
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