103121000000130 has 128 divisors (see below), whose sum is σ = 288869841174528. Its totient is φ = 23068561485312.

The previous prime is 103121000000119. The next prime is 103121000000131. The reversal of 103121000000130 is 31000000121301.

It is a super-2 number, since 2×103121000000130² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (103121000000131) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 940289679 + ... + 940399341.

It is an arithmetic number, because the mean of its divisors is an integer number (2256795634176).

Almost surely, 2^{103121000000130} is an apocalyptic number.

103121000000130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

103121000000130 is an abundant number, since it is smaller than the sum of its proper divisors (185748841174398).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103121000000130 is a wasteful number, since it uses less digits than its factorization.

103121000000130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 205000.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 103121000000130 its reverse (31000000121301), we get a palindrome (134121000121431).

The spelling of 103121000000130 in words is "one hundred three trillion, one hundred twenty-one billion, one hundred thirty", and thus it is an aban number.