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103121011303 = 791459389449
BaseRepresentation
bin110000000001001111…
…1011100001001100111
3100212011200101010212221
41200002133130021213
53142142434330203
6115212333053211
710310302063552
oct1400237341147
9325150333787
10103121011303
113a808139092
1217b9b027207
1399552b32ab
144dc3767699
152a38233abd
hex18027dc267

103121011303 has 8 divisors (see below), whose sum is σ = 104434664000. Its totient is φ = 101807566848.

The previous prime is 103121011277. The next prime is 103121011307. The reversal of 103121011303 is 303110121301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 103121011303 - 233 = 94531076711 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103121011307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1108123 + ... + 1197571.

It is an arithmetic number, because the mean of its divisors is an integer number (13054333000).

Almost surely, 2103121011303 is an apocalyptic number.

103121011303 is a deficient number, since it is larger than the sum of its proper divisors (1313652697).

103121011303 is an equidigital number, since it uses as much as digits as its factorization.

103121011303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104121.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 103121011303 its reverse (303110121301), we get a palindrome (406231132604).

The spelling of 103121011303 in words is "one hundred three billion, one hundred twenty-one million, eleven thousand, three hundred three".

Divisors: 1 79 14593 89449 1152847 7066471 1305329257 103121011303