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10312112411 is a prime number
BaseRepresentation
bin10011001101010011…
…00101100100011011
3222121200001120212022
421212221211210123
5132104400044121
64423132205055
7513354336446
oct114651454433
928550046768
1010312112411
114411a11757
121bb960978b
13c84569483
146db7aa65d
154054b0aab
hex266a6591b

10312112411 has 2 divisors, whose sum is σ = 10312112412. Its totient is φ = 10312112410.

The previous prime is 10312112387. The next prime is 10312112413. The reversal of 10312112411 is 11421121301.

10312112411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10312112411 is a prime.

Together with 10312112413, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10312112411.

It is not a weakly prime, because it can be changed into another prime (10312112413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156056205 + 5156056206.

It is an arithmetic number, because the mean of its divisors is an integer number (5156056206).

Almost surely, 210312112411 is an apocalyptic number.

10312112411 is a deficient number, since it is larger than the sum of its proper divisors (1).

10312112411 is an equidigital number, since it uses as much as digits as its factorization.

10312112411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 10312112411 its reverse (11421121301), we get a palindrome (21733233712).

The spelling of 10312112411 in words is "ten billion, three hundred twelve million, one hundred twelve thousand, four hundred eleven".