10312112431 has 2 divisors, whose sum is σ = 10312112432. Its totient is φ = 10312112430.

The previous prime is 10312112413. The next prime is 10312112441. The reversal of 10312112431 is 13421121301.

Together with previous prime (10312112413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10312112431 - 2¹⁵ = 10312079663 is a prime.

It is a super-2 number, since 2×10312112431² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10312112399 and 10312112408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10312112411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156056215 + 5156056216.

It is an arithmetic number, because the mean of its divisors is an integer number (5156056216).

Almost surely, 2^10312112431 is an apocalyptic number.

10312112431 is a deficient number, since it is larger than the sum of its proper divisors (1).

10312112431 is an equidigital number, since it uses as much as digits as its factorization.

10312112431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10312112431 its reverse (13421121301), we get a palindrome (23733233732).

The spelling of 10312112431 in words is "ten billion, three hundred twelve million, one hundred twelve thousand, four hundred thirty-one".