Base | Representation |
---|---|
bin | 1001011000001111100111… |
… | …0110000010011110111011 |
3 | 1100111211100220021202102111 |
4 | 2112003321312002132323 |
5 | 2322423201440000011 |
6 | 33533152554113151 |
7 | 2113011530655655 |
oct | 226037166023673 |
9 | 40454326252374 |
10 | 10312113203131 |
11 | 33163850810a3 |
12 | 11a6681a1b7b7 |
13 | 59a574705c3c |
14 | 279174d196d5 |
15 | 12d395c84121 |
hex | 960f9d827bb |
10312113203131 has 2 divisors, whose sum is σ = 10312113203132. Its totient is φ = 10312113203130.
The previous prime is 10312113203123. The next prime is 10312113203153. The reversal of 10312113203131 is 13130231121301.
It is an a-pointer prime, because the next prime (10312113203153) can be obtained adding 10312113203131 to its sum of digits (22).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10312113203131 - 23 = 10312113203123 is a prime.
It is a super-2 number, since 2×103121132031312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10312113203101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156056601565 + 5156056601566.
It is an arithmetic number, because the mean of its divisors is an integer number (5156056601566).
Almost surely, 210312113203131 is an apocalyptic number.
10312113203131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312113203131 is an equidigital number, since it uses as much as digits as its factorization.
10312113203131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 10312113203131 its reverse (13130231121301), we get a palindrome (23442344324432).
The spelling of 10312113203131 in words is "ten trillion, three hundred twelve billion, one hundred thirteen million, two hundred three thousand, one hundred thirty-one".
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