Base | Representation |
---|---|
bin | 11110000000110001111… |
… | …11000000011111111101 |
3 | 10122120201220000211100112 |
4 | 33000120333000133331 |
5 | 113343410044240331 |
6 | 2105422033235405 |
7 | 134334243414665 |
oct | 17003077003775 |
9 | 3576656024315 |
10 | 1031211321341 |
11 | 3683749a8643 |
12 | 147a32702b65 |
13 | 763205ba216 |
14 | 37ca76cb1a5 |
15 | 1bc568b532b |
hex | f018fc07fd |
1031211321341 has 2 divisors, whose sum is σ = 1031211321342. Its totient is φ = 1031211321340.
The previous prime is 1031211321229. The next prime is 1031211321379. The reversal of 1031211321341 is 1431231121301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 699958123225 + 331253198116 = 836635^2 + 575546^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1031211321341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1031211321841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515605660670 + 515605660671.
It is an arithmetic number, because the mean of its divisors is an integer number (515605660671).
Almost surely, 21031211321341 is an apocalyptic number.
It is an amenable number.
1031211321341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031211321341 is an equidigital number, since it uses as much as digits as its factorization.
1031211321341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1031211321341 its reverse (1431231121301), we get a palindrome (2462442442642).
The spelling of 1031211321341 in words is "one trillion, thirty-one billion, two hundred eleven million, three hundred twenty-one thousand, three hundred forty-one".
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