Base | Representation |
---|---|
bin | 1001011000001111100111… |
… | …0110011010101111100101 |
3 | 1100111211100220110210201212 |
4 | 2112003321312122233211 |
5 | 2322423202001140001 |
6 | 33533153000201205 |
7 | 2113011531551453 |
oct | 226037166325745 |
9 | 40454326423655 |
10 | 10312113302501 |
11 | 331638513981a |
12 | 11a6681a69205 |
13 | 59a57473c23a |
14 | 279174d439d3 |
15 | 12d395ca37bb |
hex | 960f9d9abe5 |
10312113302501 has 2 divisors, whose sum is σ = 10312113302502. Its totient is φ = 10312113302500.
The previous prime is 10312113302399. The next prime is 10312113302551. The reversal of 10312113302501 is 10520331121301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9033336813601 + 1278776488900 = 3005551^2 + 1130830^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10312113302501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10312113302551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156056651250 + 5156056651251.
It is an arithmetic number, because the mean of its divisors is an integer number (5156056651251).
Almost surely, 210312113302501 is an apocalyptic number.
It is an amenable number.
10312113302501 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312113302501 is an equidigital number, since it uses as much as digits as its factorization.
10312113302501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 10312113302501 its reverse (10520331121301), we get a palindrome (20832444423802).
The spelling of 10312113302501 in words is "ten trillion, three hundred twelve billion, one hundred thirteen million, three hundred two thousand, five hundred one".
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