Base | Representation |
---|---|
bin | 100111010101… |
… | …100110111001 |
3 | 201101220120102 |
4 | 213111212321 |
5 | 10114441441 |
6 | 1005005145 |
7 | 153436331 |
oct | 47254671 |
9 | 21356512 |
10 | 10312121 |
11 | 5903716 |
12 | 35537b5 |
13 | 21a0961 |
14 | 15260c1 |
15 | d8a69b |
hex | 9d59b9 |
10312121 has 2 divisors, whose sum is σ = 10312122. Its totient is φ = 10312120.
The previous prime is 10312091. The next prime is 10312123. The reversal of 10312121 is 12121301.
10312121 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10310521 + 1600 = 3211^2 + 40^2 .
It is an emirp because it is prime and its reverse (12121301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10312121 - 214 = 10295737 is a prime.
Together with 10312123, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10312123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156060 + 5156061.
It is an arithmetic number, because the mean of its divisors is an integer number (5156061).
Almost surely, 210312121 is an apocalyptic number.
It is an amenable number.
10312121 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312121 is an equidigital number, since it uses as much as digits as its factorization.
10312121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
The square root of 10312121 is about 3211.2491339041. The cubic root of 10312121 is about 217.6620257443.
Adding to 10312121 its reverse (12121301), we get a palindrome (22433422).
The spelling of 10312121 in words is "ten million, three hundred twelve thousand, one hundred twenty-one".
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