Search a number
-
+
103121210020022 = 251560605010011
BaseRepresentation
bin10111011100100111000111…
…000101111001000010110110
3111112010021212102121210122122
4113130213013011321002312
5102004014214231120042
61003153121353355542
730502155500442035
oct2734470705710266
9445107772553578
10103121210020022
112a948506767a17
12b6956b8708bb2
13457039975238c
141b67143a2c71c
15bdc6453337d2
hex5dc9c71790b6

103121210020022 has 4 divisors (see below), whose sum is σ = 154681815030036. Its totient is φ = 51560605010010.

The previous prime is 103121210020021. The next prime is 103121210020067. The reversal of 103121210020022 is 220020012121301.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103121210020021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25780302505004 + ... + 25780302505007.

It is an arithmetic number, because the mean of its divisors is an integer number (38670453757509).

Almost surely, 2103121210020022 is an apocalyptic number.

103121210020022 is a deficient number, since it is larger than the sum of its proper divisors (51560605010014).

103121210020022 is an equidigital number, since it uses as much as digits as its factorization.

103121210020022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51560605010013.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 103121210020022 its reverse (220020012121301), we get a palindrome (323141222141323).

The spelling of 103121210020022 in words is "one hundred three trillion, one hundred twenty-one billion, two hundred ten million, twenty thousand, twenty-two".

Divisors: 1 2 51560605010011 103121210020022