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103121210020110 = 23531110883021527
BaseRepresentation
bin10111011100100111000111…
…000101111001000100001110
3111112010021212102121210202220
4113130213013011321010032
5102004014214231120420
61003153121353400210
730502155500442222
oct2734470705710416
9445107772553686
10103121210020110
112a948506767a97
12b6956b8709066
134570399752429
141b67143a2c782
15bdc645333840
hex5dc9c717910e

103121210020110 has 32 divisors (see below), whose sum is σ = 255474481600512. Its totient is φ = 26611925166240.

The previous prime is 103121210020109. The next prime is 103121210020111. The reversal of 103121210020110 is 11020012121301.

It is an interprime number because it is at equal distance from previous prime (103121210020109) and next prime (103121210020111).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 103121210020110.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103121210020111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 55441509834 + ... + 55441511693.

It is an arithmetic number, because the mean of its divisors is an integer number (7983577550016).

Almost surely, 2103121210020110 is an apocalyptic number.

103121210020110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

103121210020110 is an abundant number, since it is smaller than the sum of its proper divisors (152353271580402).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103121210020110 is a wasteful number, since it uses less digits than its factorization.

103121210020110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110883021568.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 103121210020110 its reverse (11020012121301), we get a palindrome (114141222141411).

The spelling of 103121210020110 in words is "one hundred three trillion, one hundred twenty-one billion, two hundred ten million, twenty thousand, one hundred ten".

Divisors: 1 2 3 5 6 10 15 30 31 62 93 155 186 310 465 930 110883021527 221766043054 332649064581 554415107635 665298129162 1108830215270 1663245322905 3326490645810 3437373667337 6874747334674 10312121002011 17186868336685 20624242004022 34373736673370 51560605010055 103121210020110