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10312121201153 is a prime number
BaseRepresentation
bin1001011000001111101001…
…0100100011001000000001
31100111211101110100002122112
42112003322110203020001
52322423211011414103
633533153441345105
72113011655646552
oct226037224431001
940454343302575
1010312121201153
113316389644132
1211a6684638195
1359a5762764b5
14279175ddc329
1512d396813cd8
hex960fa523201

10312121201153 has 2 divisors, whose sum is σ = 10312121201154. Its totient is φ = 10312121201152.

The previous prime is 10312121201131. The next prime is 10312121201189. The reversal of 10312121201153 is 35110212121301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9986819797249 + 325301403904 = 3160193^2 + 570352^2 .

It is a cyclic number.

It is not a de Polignac number, because 10312121201153 - 230 = 10311047459329 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (10312121201113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156060600576 + 5156060600577.

It is an arithmetic number, because the mean of its divisors is an integer number (5156060600577).

Almost surely, 210312121201153 is an apocalyptic number.

It is an amenable number.

10312121201153 is a deficient number, since it is larger than the sum of its proper divisors (1).

10312121201153 is an equidigital number, since it uses as much as digits as its factorization.

10312121201153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 10312121201153 its reverse (35110212121301), we get a palindrome (45422333322454).

The spelling of 10312121201153 in words is "ten trillion, three hundred twelve billion, one hundred twenty-one million, two hundred one thousand, one hundred fifty-three".