Base | Representation |
---|---|
bin | 1001011000001111101011… |
… | …0110010011110000001111 |
3 | 1100111211102001222201110212 |
4 | 2112003322312103300033 |
5 | 2322423220243113322 |
6 | 33533154355153035 |
7 | 2113012124116244 |
oct | 226037266236017 |
9 | 40454361881425 |
10 | 10312130051087 |
11 | 3316393639227 |
12 | 11a66875a577b |
13 | 59a578054747 |
14 | 2791772635cb |
15 | 12d3974b10e2 |
hex | 960fad93c0f |
10312130051087 has 2 divisors, whose sum is σ = 10312130051088. Its totient is φ = 10312130051086.
The previous prime is 10312130051053. The next prime is 10312130051101. The reversal of 10312130051087 is 78015003121301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10312130051087 - 230 = 10311056309263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10312130051287) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156065025543 + 5156065025544.
It is an arithmetic number, because the mean of its divisors is an integer number (5156065025544).
Almost surely, 210312130051087 is an apocalyptic number.
10312130051087 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312130051087 is an equidigital number, since it uses as much as digits as its factorization.
10312130051087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 32.
Adding to 10312130051087 its reverse (78015003121301), we get a palindrome (88327133172388).
The spelling of 10312130051087 in words is "ten trillion, three hundred twelve billion, one hundred thirty million, fifty-one thousand, eighty-seven".
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