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103124004433541 = 7131133230817951
BaseRepresentation
bin10111011100101001101101…
…101001101110111010000101
3111112010120002011210201100122
4113130221231221232322011
5102004040430113333131
61003154302535351325
730502314651532160
oct2734515551567205
9445116064721318
10103124004433541
112a94971007a183
12b696158522545
1345707236748c0
141b6732abdaad7
15bdc75a817d7b
hex5dca6da6ee85

103124004433541 has 8 divisors (see below), whose sum is σ = 126921851610624. Its totient is φ = 81592618892400.

The previous prime is 103124004433531. The next prime is 103124004433543. The reversal of 103124004433541 is 145334400421301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-103124004433541 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103124004433543) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 566615408885 + ... + 566615409066.

It is an arithmetic number, because the mean of its divisors is an integer number (15865231451328).

Almost surely, 2103124004433541 is an apocalyptic number.

It is an amenable number.

103124004433541 is a deficient number, since it is larger than the sum of its proper divisors (23797847177083).

103124004433541 is a wasteful number, since it uses less digits than its factorization.

103124004433541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1133230817971.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 103124004433541 its reverse (145334400421301), we get a palindrome (248458404854842).

The spelling of 103124004433541 in words is "one hundred three trillion, one hundred twenty-four billion, four million, four hundred thirty-three thousand, five hundred forty-one".

Divisors: 1 7 13 91 1133230817951 7932615725657 14732000633363 103124004433541