Base | Representation |
---|---|
bin | 110000000001010110… |
… | …0001001100100001111 |
3 | 100212011220122102012011 |
4 | 1200002230021210033 |
5 | 3142144312434210 |
6 | 115212532322051 |
7 | 10310342311246 |
oct | 1400254114417 |
9 | 325156572164 |
10 | 103124343055 |
11 | 3a80a0042a8 |
12 | 17ba0173327 |
13 | 9955bab946 |
14 | 4dc3d9395d |
15 | 2a38690d8a |
hex | 1802b0990f |
103124343055 has 4 divisors (see below), whose sum is σ = 123749211672. Its totient is φ = 82499474440.
The previous prime is 103124343037. The next prime is 103124343067. The reversal of 103124343055 is 550343421301.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 550343421301 = 241 ⋅2283582661.
It is not a de Polignac number, because 103124343055 - 29 = 103124342543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10312434301 + ... + 10312434310.
It is an arithmetic number, because the mean of its divisors is an integer number (30937302918).
Almost surely, 2103124343055 is an apocalyptic number.
103124343055 is a deficient number, since it is larger than the sum of its proper divisors (20624868617).
103124343055 is an equidigital number, since it uses as much as digits as its factorization.
103124343055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20624868616.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 103124343055 its reverse (550343421301), we get a palindrome (653467764356).
The spelling of 103124343055 in words is "one hundred three billion, one hundred twenty-four million, three hundred forty-three thousand, fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •