10313001235 has 4 divisors (see below), whose sum is σ = 12375601488. Its totient is φ = 8250400984.

The previous prime is 10313001233. The next prime is 10313001247. The reversal of 10313001235 is 53210031301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53210031301 = 7 ⋅7601433043.

It is a cyclic number.

It is not a de Polignac number, because 10313001235 - 2¹ = 10313001233 is a prime.

It is a super-2 number, since 2×10313001235² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10313001233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1031300119 + ... + 1031300128.

It is an arithmetic number, because the mean of its divisors is an integer number (3093900372).

Almost surely, 2^10313001235 is an apocalyptic number.

10313001235 is a deficient number, since it is larger than the sum of its proper divisors (2062600253).

10313001235 is an equidigital number, since it uses as much as digits as its factorization.

10313001235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2062600252.

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 10313001235 its reverse (53210031301), we get a palindrome (63523032536).

The spelling of 10313001235 in words is "ten billion, three hundred thirteen million, one thousand, two hundred thirty-five".