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10313003013 = 33437667671
BaseRepresentation
bin10011001101011001…
…11111000000000101
3222121201201211112120
421212230333000011
5132110112044023
64423203240153
7513365036115
oct114654770005
928551654476
1010313003013
11441246a895
121bb9979059
13c847bb961
146db95d045
154055d98e3
hex266b3f005

10313003013 has 4 divisors (see below), whose sum is σ = 13750670688. Its totient is φ = 6875335340.

The previous prime is 10313003011. The next prime is 10313003021. The reversal of 10313003013 is 31030031301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10313003013 - 21 = 10313003011 is a prime.

It is a super-2 number, since 2×103130030132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10313002983 and 10313003001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10313003011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1718833833 + ... + 1718833838.

It is an arithmetic number, because the mean of its divisors is an integer number (3437667672).

Almost surely, 210313003013 is an apocalyptic number.

It is an amenable number.

10313003013 is a deficient number, since it is larger than the sum of its proper divisors (3437667675).

10313003013 is an equidigital number, since it uses as much as digits as its factorization.

10313003013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3437667674.

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 10313003013 its reverse (31030031301), we get a palindrome (41343034314).

The spelling of 10313003013 in words is "ten billion, three hundred thirteen million, three thousand, thirteen".

Divisors: 1 3 3437667671 10313003013