10313003021 has 2 divisors, whose sum is σ = 10313003022. Its totient is φ = 10313003020.

The previous prime is 10313003011. The next prime is 10313003023. The reversal of 10313003021 is 12030031301.

10313003021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10243464100 + 69538921 = 101210^2 + 8339^2 .

It is a cyclic number.

It is not a de Polignac number, because 10313003021 - 2³⁰ = 9239261197 is a prime.

It is a super-2 number, since 2×10313003021² (a number of 21 digits) contains 22 as substring.

Together with 10313003023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10313002987 and 10313003005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10313003023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156501510 + 5156501511.

It is an arithmetic number, because the mean of its divisors is an integer number (5156501511).

Almost surely, 2^10313003021 is an apocalyptic number.

It is an amenable number.

10313003021 is a deficient number, since it is larger than the sum of its proper divisors (1).

10313003021 is an equidigital number, since it uses as much as digits as its factorization.

10313003021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 10313003021 its reverse (12030031301), we get a palindrome (22343034322).

The spelling of 10313003021 in words is "ten billion, three hundred thirteen million, three thousand, twenty-one".