103130031301 has 4 divisors (see below), whose sum is σ = 112505488704. Its totient is φ = 93754573900.

The previous prime is 103130031283. The next prime is 103130031317.

103130031301 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103130031301 - 2¹⁷ = 103129900229 is a prime.

It is a super-2 number, since 2×103130031301² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103130031001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4687728685 + ... + 4687728706.

It is an arithmetic number, because the mean of its divisors is an integer number (28126372176).

Almost surely, 2^103130031301 is an apocalyptic number.

103130031301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

103130031301 is a deficient number, since it is larger than the sum of its proper divisors (9375457403).

103130031301 is an equidigital number, since it uses as much as digits as its factorization.

103130031301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9375457402.

The product of its (nonzero) digits is 81, while the sum is 16.

It can be divided in two parts, 1031300 and 31301, that added together give a palindrome (1062601).

The spelling of 103130031301 in words is "one hundred three billion, one hundred thirty million, thirty-one thousand, three hundred one".