Search a number
-
+
103130044453 is a prime number
BaseRepresentation
bin110000000001100000…
…1111001100000100101
3100212012022101002001001
41200003001321200211
53142202242410303
6115213254433301
710310441625352
oct1400301714045
9325168332031
10103130044453
113a8122488a7
1217ba2062831
139957126a57
144dc4a39629
152a38e1a31d
hex1803079825

103130044453 has 2 divisors, whose sum is σ = 103130044454. Its totient is φ = 103130044452.

The previous prime is 103130044403. The next prime is 103130044513. The reversal of 103130044453 is 354440031301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86225624164 + 16904420289 = 293642^2 + 130017^2 .

It is an emirp because it is prime and its reverse (354440031301) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103130044453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103130044403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51565022226 + 51565022227.

It is an arithmetic number, because the mean of its divisors is an integer number (51565022227).

Almost surely, 2103130044453 is an apocalyptic number.

It is an amenable number.

103130044453 is a deficient number, since it is larger than the sum of its proper divisors (1).

103130044453 is an equidigital number, since it uses as much as digits as its factorization.

103130044453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 103130044453 its reverse (354440031301), we get a palindrome (457570075754).

The spelling of 103130044453 in words is "one hundred three billion, one hundred thirty million, forty-four thousand, four hundred fifty-three".