Base | Representation |
---|---|
bin | 110000000001100001… |
… | …0111000000000000111 |
3 | 100212012022212002011102 |
4 | 1200003002320000013 |
5 | 3142202324103143 |
6 | 115213304130315 |
7 | 10310444042543 |
oct | 1400302700007 |
9 | 325168762142 |
10 | 103130300423 |
11 | 3a812403147 |
12 | 17ba216699b |
13 | 99571b6407 |
14 | 4dc4aa4a23 |
15 | 2a38e6b0b8 |
hex | 18030b8007 |
103130300423 has 2 divisors, whose sum is σ = 103130300424. Its totient is φ = 103130300422.
The previous prime is 103130300407. The next prime is 103130300473. The reversal of 103130300423 is 324003031301.
It is a weak prime.
It is an emirp because it is prime and its reverse (324003031301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103130300423 - 24 = 103130300407 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 103130300395 and 103130300404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103130300473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51565150211 + 51565150212.
It is an arithmetic number, because the mean of its divisors is an integer number (51565150212).
Almost surely, 2103130300423 is an apocalyptic number.
103130300423 is a deficient number, since it is larger than the sum of its proper divisors (1).
103130300423 is an equidigital number, since it uses as much as digits as its factorization.
103130300423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 103130300423 its reverse (324003031301), we get a palindrome (427133331724).
The spelling of 103130300423 in words is "one hundred three billion, one hundred thirty million, three hundred thousand, four hundred twenty-three".
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