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103131030113 = 2331145999139
BaseRepresentation
bin110000000001100010…
…1101010001001100001
3100212012101020011002222
41200003011222021201
53142203020430423
6115213331520425
710310453202116
oct1400305521141
9325171204088
10103131030113
113a8128613a1
1217ba2459115
1399573b0597
144dc4c1490d
152a390623c8
hex180316a261

103131030113 has 16 divisors (see below), whose sum is σ = 111163699200. Its totient is φ = 95398514640.

The previous prime is 103131030103. The next prime is 103131030131. The reversal of 103131030113 is 311030131301.

It is not a de Polignac number, because 103131030113 - 24 = 103131030097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 103131030091 and 103131030100.

It is not an unprimeable number, because it can be changed into a prime (103131030103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 990698 + ... + 1089836.

It is an arithmetic number, because the mean of its divisors is an integer number (6947731200).

Almost surely, 2103131030113 is an apocalyptic number.

It is an amenable number.

103131030113 is a deficient number, since it is larger than the sum of its proper divisors (8032669087).

103131030113 is a wasteful number, since it uses less digits than its factorization.

103131030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100652.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 103131030113 its reverse (311030131301), we get a palindrome (414161161414).

The spelling of 103131030113 in words is "one hundred three billion, one hundred thirty-one million, thirty thousand, one hundred thirteen".

Divisors: 1 23 31 713 1459 33557 45229 99139 1040267 2280197 3073309 70686107 144643801 3326807423 4483957831 103131030113