Base | Representation |
---|---|
bin | 110000000001100010… |
… | …1101010001001100001 |
3 | 100212012101020011002222 |
4 | 1200003011222021201 |
5 | 3142203020430423 |
6 | 115213331520425 |
7 | 10310453202116 |
oct | 1400305521141 |
9 | 325171204088 |
10 | 103131030113 |
11 | 3a8128613a1 |
12 | 17ba2459115 |
13 | 99573b0597 |
14 | 4dc4c1490d |
15 | 2a390623c8 |
hex | 180316a261 |
103131030113 has 16 divisors (see below), whose sum is σ = 111163699200. Its totient is φ = 95398514640.
The previous prime is 103131030103. The next prime is 103131030131. The reversal of 103131030113 is 311030131301.
It is not a de Polignac number, because 103131030113 - 24 = 103131030097 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 103131030091 and 103131030100.
It is not an unprimeable number, because it can be changed into a prime (103131030103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 990698 + ... + 1089836.
It is an arithmetic number, because the mean of its divisors is an integer number (6947731200).
Almost surely, 2103131030113 is an apocalyptic number.
It is an amenable number.
103131030113 is a deficient number, since it is larger than the sum of its proper divisors (8032669087).
103131030113 is a wasteful number, since it uses less digits than its factorization.
103131030113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100652.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 103131030113 its reverse (311030131301), we get a palindrome (414161161414).
The spelling of 103131030113 in words is "one hundred three billion, one hundred thirty-one million, thirty thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •