Base | Representation |
---|---|
bin | 10111011100110000010110… |
… | …011011111011110010101101 |
3 | 111112011020110211221120021012 |
4 | 113130300112123323302231 |
5 | 102004200024032224401 |
6 | 1003201442041315005 |
7 | 30502656366505001 |
oct | 2734602633736255 |
9 | 445136424846235 |
10 | 103131131133101 |
11 | 2a9517379a1025 |
12 | b697607195a65 |
13 | 45712bacabca6 |
14 | 1b678054d8701 |
15 | bdca2630c8bb |
hex | 5dcc166fbcad |
103131131133101 has 2 divisors, whose sum is σ = 103131131133102. Its totient is φ = 103131131133100.
The previous prime is 103131131133083. The next prime is 103131131133113. The reversal of 103131131133101 is 101331131131301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 63575522177476 + 39555608955625 = 7973426^2 + 6289325^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103131131133101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103131131133181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51565565566550 + 51565565566551.
It is an arithmetic number, because the mean of its divisors is an integer number (51565565566551).
Almost surely, 2103131131133101 is an apocalyptic number.
It is an amenable number.
103131131133101 is a deficient number, since it is larger than the sum of its proper divisors (1).
103131131133101 is an equidigital number, since it uses as much as digits as its factorization.
103131131133101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 23.
Adding to 103131131133101 its reverse (101331131131301), we get a palindrome (204462262264402).
The spelling of 103131131133101 in words is "one hundred three trillion, one hundred thirty-one billion, one hundred thirty-one million, one hundred thirty-three thousand, one hundred one".
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