Base | Representation |
---|---|
bin | 110000000001100011… |
… | …0101110100000010001 |
3 | 100212012101202101011202 |
4 | 1200003012232200101 |
5 | 3142203103410342 |
6 | 115213341520545 |
7 | 10310455446314 |
oct | 1400306564021 |
9 | 325171671152 |
10 | 103131310097 |
11 | 3a812a32792 |
12 | 17ba2573155 |
13 | 995747ab5a |
14 | 4dc4c8897b |
15 | 2a390ba332 |
hex | 18031ae811 |
103131310097 has 2 divisors, whose sum is σ = 103131310098. Its totient is φ = 103131310096.
The previous prime is 103131310031. The next prime is 103131310099. The reversal of 103131310097 is 790013131301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95758683601 + 7372626496 = 309449^2 + 85864^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103131310097 is a prime.
Together with 103131310099, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (103131310099) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51565655048 + 51565655049.
It is an arithmetic number, because the mean of its divisors is an integer number (51565655049).
Almost surely, 2103131310097 is an apocalyptic number.
It is an amenable number.
103131310097 is a deficient number, since it is larger than the sum of its proper divisors (1).
103131310097 is an equidigital number, since it uses as much as digits as its factorization.
103131310097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1701, while the sum is 29.
Adding to 103131310097 its reverse (790013131301), we get a palindrome (893144441398).
The spelling of 103131310097 in words is "one hundred three billion, one hundred thirty-one million, three hundred ten thousand, ninety-seven".
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