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10313141421455 = 56133813578431
BaseRepresentation
bin1001011000010011011100…
…1000011000010110001111
31100111221000120001122210122
42112010313020120112033
52322432303200441310
633533443004255155
72113046154455015
oct226046710302617
940457016048718
1010313141421455
113316862518804
1211a690a2414bb
1359a6a9743152
142792316d08b5
1512d40618b555
hex9613721858f

10313141421455 has 8 divisors (see below), whose sum is σ = 12578651176704. Its totient is φ = 8115258823200.

The previous prime is 10313141421433. The next prime is 10313141421487. The reversal of 10313141421455 is 55412414131301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10313141421455 - 26 = 10313141421391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16906788911 + ... + 16906789520.

It is an arithmetic number, because the mean of its divisors is an integer number (1572331397088).

Almost surely, 210313141421455 is an apocalyptic number.

10313141421455 is a deficient number, since it is larger than the sum of its proper divisors (2265509755249).

10313141421455 is an equidigital number, since it uses as much as digits as its factorization.

10313141421455 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33813578497.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 10313141421455 its reverse (55412414131301), we get a palindrome (65725555552756).

The spelling of 10313141421455 in words is "ten trillion, three hundred thirteen billion, one hundred forty-one million, four hundred twenty-one thousand, four hundred fifty-five".

Divisors: 1 5 61 305 33813578431 169067892155 2062628284291 10313141421455