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10313154324231 = 3112313587818609
BaseRepresentation
bin1001011000010011011111…
…1001100110011100000111
31100111221001110100012002020
42112010313321212130013
52322432320001333411
633533444145014223
72113046402234313
oct226046771463407
940457043305066
1010313154324231
113316869830860
1211a6912624373
1359a6ac310025
142792332ccb43
1512d407389606
hex96137e66707

10313154324231 has 16 divisors (see below), whose sum is σ = 15653167038720. Its totient is φ = 5978640187520.

The previous prime is 10313154324181. The next prime is 10313154324233. The reversal of 10313154324231 is 13242345131301.

It is not a de Polignac number, because 10313154324231 - 222 = 10313150129927 is a prime.

It is a super-2 number, since 2×103131543242312 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is a junction number, because it is equal to n+sod(n) for n = 10313154324192 and 10313154324201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10313154324233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6793908546 + ... + 6793910063.

It is an arithmetic number, because the mean of its divisors is an integer number (978322939920).

Almost surely, 210313154324231 is an apocalyptic number.

10313154324231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

10313154324231 is a deficient number, since it is larger than the sum of its proper divisors (5340012714489).

10313154324231 is a wasteful number, since it uses less digits than its factorization.

10313154324231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13587818646.

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 10313154324231 its reverse (13242345131301), we get a palindrome (23555499455532).

The spelling of 10313154324231 in words is "ten trillion, three hundred thirteen billion, one hundred fifty-four million, three hundred twenty-four thousand, two hundred thirty-one".

Divisors: 1 3 11 23 33 69 253 759 13587818609 40763455827 149466004699 312519828007 448398014097 937559484021 3437718108077 10313154324231