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10313223221957 is a prime number
BaseRepresentation
bin1001011000010011110000…
…0000011011001011000101
31100111221020020222112222212
42112010330000123023011
52322432440121100312
633533455045433205
72113051166660315
oct226047400331305
940457206875885
1010313223221957
1133168a4709727
1211a693170b805
1359a6c0683c06
1427923c505445
1512d40d448822
hex9613c01b2c5

10313223221957 has 2 divisors, whose sum is σ = 10313223221958. Its totient is φ = 10313223221956.

The previous prime is 10313223221941. The next prime is 10313223221981. The reversal of 10313223221957 is 75912232231301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8945518700836 + 1367704521121 = 2990906^2 + 1169489^2 .

It is a cyclic number.

It is not a de Polignac number, because 10313223221957 - 24 = 10313223221941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10313223220957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156611610978 + 5156611610979.

It is an arithmetic number, because the mean of its divisors is an integer number (5156611610979).

Almost surely, 210313223221957 is an apocalyptic number.

It is an amenable number.

10313223221957 is a deficient number, since it is larger than the sum of its proper divisors (1).

10313223221957 is an equidigital number, since it uses as much as digits as its factorization.

10313223221957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 41.

The spelling of 10313223221957 in words is "ten trillion, three hundred thirteen billion, two hundred twenty-three million, two hundred twenty-one thousand, nine hundred fifty-seven".