Base | Representation |
---|---|
bin | 11110000001000000010… |
… | …00011101110010110111 |
3 | 10122121001020200101101200 |
4 | 33000200020131302313 |
5 | 113344131244204033 |
6 | 2105441555423543 |
7 | 134340230623260 |
oct | 17004010356267 |
9 | 3577036611350 |
10 | 1031331241143 |
11 | 368426665115 |
12 | 147a668b4bb3 |
13 | 7633c3b6798 |
14 | 37cb95c5967 |
15 | 1bc621a2013 |
hex | f02021dcb7 |
1031331241143 has 12 divisors (see below), whose sum is σ = 1702515064848. Its totient is φ = 589332137760.
The previous prime is 1031331241121. The next prime is 1031331241151. The reversal of 1031331241143 is 3411421331301.
1031331241143 is a `hidden beast` number, since 103 + 133 + 12 + 411 + 4 + 3 = 666.
It is not a de Polignac number, because 1031331241143 - 217 = 1031331110071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1031331241243) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8185168518 + ... + 8185168643.
It is an arithmetic number, because the mean of its divisors is an integer number (141876255404).
Almost surely, 21031331241143 is an apocalyptic number.
1031331241143 is a deficient number, since it is larger than the sum of its proper divisors (671183823705).
1031331241143 is a wasteful number, since it uses less digits than its factorization.
1031331241143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16370337174 (or 16370337171 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 1031331241143 its reverse (3411421331301), we get a palindrome (4442752572444).
The spelling of 1031331241143 in words is "one trillion, thirty-one billion, three hundred thirty-one million, two hundred forty-one thousand, one hundred forty-three".
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