10313414433 has 12 divisors (see below), whose sum is σ = 17025319168. Its totient is φ = 5893379640.

The previous prime is 10313414431. The next prime is 10313414437. The reversal of 10313414433 is 33441431301.

10313414433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10313414433 - 2¹ = 10313414431 is a prime.

It is a super-2 number, since 2×10313414433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10313414397 and 10313414406.

It is not an unprimeable number, because it can be changed into a prime (10313414431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 81852433 + ... + 81852558.

Almost surely, 2^10313414433 is an apocalyptic number.

It is an amenable number.

10313414433 is a deficient number, since it is larger than the sum of its proper divisors (6711904735).

10313414433 is a wasteful number, since it uses less digits than its factorization.

10313414433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163705004 (or 163705001 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 10313414433 its reverse (33441431301), we get a palindrome (43754845734).

The spelling of 10313414433 in words is "ten billion, three hundred thirteen million, four hundred fourteen thousand, four hundred thirty-three".