Base | Representation |
---|---|
bin | 110000000001101001… |
… | …0001011111100001011 |
3 | 100212012121102000002201 |
4 | 1200003102023330023 |
5 | 3142204341024001 |
6 | 115213530141031 |
7 | 10310523130633 |
oct | 1400322137413 |
9 | 325177360081 |
10 | 103134314251 |
11 | 3a8146a4861 |
12 | 17ba3581777 |
13 | 9957c90367 |
14 | 4dc542b6c3 |
15 | 2a394b0501 |
hex | 180348bf0b |
103134314251 has 2 divisors, whose sum is σ = 103134314252. Its totient is φ = 103134314250.
The previous prime is 103134314249. The next prime is 103134314279. The reversal of 103134314251 is 152413431301.
It is an a-pointer prime, because the next prime (103134314279) can be obtained adding 103134314251 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103134314251 - 21 = 103134314249 is a prime.
Together with 103134314249, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (103134314551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51567157125 + 51567157126.
It is an arithmetic number, because the mean of its divisors is an integer number (51567157126).
Almost surely, 2103134314251 is an apocalyptic number.
103134314251 is a deficient number, since it is larger than the sum of its proper divisors (1).
103134314251 is an equidigital number, since it uses as much as digits as its factorization.
103134314251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 103134314251 its reverse (152413431301), we get a palindrome (255547745552).
The spelling of 103134314251 in words is "one hundred three billion, one hundred thirty-four million, three hundred fourteen thousand, two hundred fifty-one".
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