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103134314251 is a prime number
BaseRepresentation
bin110000000001101001…
…0001011111100001011
3100212012121102000002201
41200003102023330023
53142204341024001
6115213530141031
710310523130633
oct1400322137413
9325177360081
10103134314251
113a8146a4861
1217ba3581777
139957c90367
144dc542b6c3
152a394b0501
hex180348bf0b

103134314251 has 2 divisors, whose sum is σ = 103134314252. Its totient is φ = 103134314250.

The previous prime is 103134314249. The next prime is 103134314279. The reversal of 103134314251 is 152413431301.

It is an a-pointer prime, because the next prime (103134314279) can be obtained adding 103134314251 to its sum of digits (28).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 103134314251 - 21 = 103134314249 is a prime.

Together with 103134314249, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (103134314551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51567157125 + 51567157126.

It is an arithmetic number, because the mean of its divisors is an integer number (51567157126).

Almost surely, 2103134314251 is an apocalyptic number.

103134314251 is a deficient number, since it is larger than the sum of its proper divisors (1).

103134314251 is an equidigital number, since it uses as much as digits as its factorization.

103134314251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 103134314251 its reverse (152413431301), we get a palindrome (255547745552).

The spelling of 103134314251 in words is "one hundred three billion, one hundred thirty-four million, three hundred fourteen thousand, two hundred fifty-one".