Base | Representation |
---|---|
bin | 110000000001101001… |
… | …0101000100001000101 |
3 | 100212012121121221122220 |
4 | 1200003102220201011 |
5 | 3142204403300201 |
6 | 115213532442553 |
7 | 10310524126116 |
oct | 1400322504105 |
9 | 325177557586 |
10 | 103134431301 |
11 | 3a8147747a0 |
12 | 17ba3619459 |
13 | 9958001715 |
14 | 4dc545c20d |
15 | 2a394d5036 |
hex | 18034a8845 |
103134431301 has 16 divisors (see below), whose sum is σ = 158838055488. Its totient is φ = 58828908800.
The previous prime is 103134431299. The next prime is 103134431347.
103134431301 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 103134431301 - 21 = 103134431299 is a prime.
It is a super-3 number, since 3×1031344313013 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103134431381) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91919610 + ... + 91920731.
It is an arithmetic number, because the mean of its divisors is an integer number (9927378468).
Almost surely, 2103134431301 is an apocalyptic number.
103134431301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
103134431301 is a deficient number, since it is larger than the sum of its proper divisors (55703624187).
103134431301 is a wasteful number, since it uses less digits than its factorization.
103134431301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183840372.
The product of its (nonzero) digits is 1296, while the sum is 24.
It can be divided in two parts, 103134 and 431301, that added together give a palindrome (534435).
The spelling of 103134431301 in words is "one hundred three billion, one hundred thirty-four million, four hundred thirty-one thousand, three hundred one".
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