103141211310141 has 4 divisors (see below), whose sum is σ = 137521615080192. Its totient is φ = 68760807540092.

The previous prime is 103141211310107. The next prime is 103141211310157. The reversal of 103141211310141 is 141013112141301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103141211310141 - 2¹³ = 103141211301949 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103141211310101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17190201885021 + ... + 17190201885026.

It is an arithmetic number, because the mean of its divisors is an integer number (34380403770048).

Almost surely, 2^{103141211310141} is an apocalyptic number.

It is an amenable number.

103141211310141 is a deficient number, since it is larger than the sum of its proper divisors (34380403770051).

103141211310141 is an equidigital number, since it uses as much as digits as its factorization.

103141211310141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34380403770050.

The product of its (nonzero) digits is 288, while the sum is 24.

Adding to 103141211310141 its reverse (141013112141301), we get a palindrome (244154323451442).

The spelling of 103141211310141 in words is "one hundred three trillion, one hundred forty-one billion, two hundred eleven million, three hundred ten thousand, one hundred forty-one".