103141255181 has 2 divisors, whose sum is σ = 103141255182. Its totient is φ = 103141255180.

The previous prime is 103141255159. The next prime is 103141255183. The reversal of 103141255181 is 181552141301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75235552681 + 27905702500 = 274291^2 + 167050^2 .

It is a cyclic number.

It is not a de Polignac number, because 103141255181 - 2¹⁰ = 103141254157 is a prime.

It is a super-2 number, since 2×103141255181² (a number of 23 digits) contains 22 as substring.

Together with 103141255183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103141255183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51570627590 + 51570627591.

It is an arithmetic number, because the mean of its divisors is an integer number (51570627591).

Almost surely, 2^103141255181 is an apocalyptic number.

It is an amenable number.

103141255181 is a deficient number, since it is larger than the sum of its proper divisors (1).

103141255181 is an equidigital number, since it uses as much as digits as its factorization.

103141255181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 32.

Adding to 103141255181 its reverse (181552141301), we get a palindrome (284693396482).

The spelling of 103141255181 in words is "one hundred three billion, one hundred forty-one million, two hundred fifty-five thousand, one hundred eighty-one".