Base | Representation |
---|---|
bin | 110000000001110110… |
… | …1001110001011110011 |
3 | 100212020002202001202011 |
4 | 1200003231032023303 |
5 | 3142213144320311 |
6 | 115214342103351 |
7 | 10310640305653 |
oct | 1400355161363 |
9 | 325202661664 |
10 | 103141401331 |
11 | 3a8186a5451 |
12 | 17ba5a1ab57 |
13 | 99595a20b7 |
14 | 4dc6354363 |
15 | 2a39e10321 |
hex | 1803b4e2f3 |
103141401331 has 2 divisors, whose sum is σ = 103141401332. Its totient is φ = 103141401330.
The previous prime is 103141401329. The next prime is 103141401353. The reversal of 103141401331 is 133104141301.
It is an a-pointer prime, because the next prime (103141401353) can be obtained adding 103141401331 to its sum of digits (22).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103141401331 - 21 = 103141401329 is a prime.
It is a super-2 number, since 2×1031414013312 (a number of 23 digits) contains 22 as substring.
Together with 103141401329, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (103141401031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51570700665 + 51570700666.
It is an arithmetic number, because the mean of its divisors is an integer number (51570700666).
Almost surely, 2103141401331 is an apocalyptic number.
103141401331 is a deficient number, since it is larger than the sum of its proper divisors (1).
103141401331 is an equidigital number, since it uses as much as digits as its factorization.
103141401331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 103141401331 its reverse (133104141301), we get a palindrome (236245542632).
The spelling of 103141401331 in words is "one hundred three billion, one hundred forty-one million, four hundred one thousand, three hundred thirty-one".
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