Base | Representation |
---|---|
bin | 1001011000010111011011… |
… | …1101011101100111111111 |
3 | 1100112000210012002222210112 |
4 | 2112011312331131213333 |
5 | 2322442001322120221 |
6 | 33534141141100235 |
7 | 2113114540005512 |
oct | 226056675354777 |
9 | 40460705088715 |
10 | 10314212301311 |
11 | 3317261a53686 |
12 | 11a6b689b767b |
13 | 59a81a569479 |
14 | 2792d3a0cd79 |
15 | 12d46a1be15b |
hex | 96176f5d9ff |
10314212301311 has 2 divisors, whose sum is σ = 10314212301312. Its totient is φ = 10314212301310.
The previous prime is 10314212301307. The next prime is 10314212301317. The reversal of 10314212301311 is 11310321241301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10314212301311 - 22 = 10314212301307 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10314212301317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157106150655 + 5157106150656.
It is an arithmetic number, because the mean of its divisors is an integer number (5157106150656).
Almost surely, 210314212301311 is an apocalyptic number.
10314212301311 is a deficient number, since it is larger than the sum of its proper divisors (1).
10314212301311 is an equidigital number, since it uses as much as digits as its factorization.
10314212301311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 10314212301311 its reverse (11310321241301), we get a palindrome (21624533542612).
The spelling of 10314212301311 in words is "ten trillion, three hundred fourteen billion, two hundred twelve million, three hundred one thousand, three hundred eleven".
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