Base | Representation |
---|---|
bin | 10011001101101100… |
… | …01000111110000111 |
3 | 222121220020202220021 |
4 | 21212312020332013 |
5 | 132111220400033 |
6 | 4423330520011 |
7 | 513424323433 |
oct | 114666107607 |
9 | 28556222807 |
10 | 10315403143 |
11 | 441385a071 |
12 | 1bba736007 |
13 | c8514c256 |
14 | 6dbdc59c3 |
15 | 405910b2d |
hex | 266d88f87 |
10315403143 has 2 divisors, whose sum is σ = 10315403144. Its totient is φ = 10315403142.
The previous prime is 10315403113. The next prime is 10315403167. The reversal of 10315403143 is 34130451301.
It is a strong prime.
It is an emirp because it is prime and its reverse (34130451301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10315403143 is a prime.
It is a super-2 number, since 2×103154031432 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10315403113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157701571 + 5157701572.
It is an arithmetic number, because the mean of its divisors is an integer number (5157701572).
Almost surely, 210315403143 is an apocalyptic number.
10315403143 is a deficient number, since it is larger than the sum of its proper divisors (1).
10315403143 is an equidigital number, since it uses as much as digits as its factorization.
10315403143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 10315403143 its reverse (34130451301), we get a palindrome (44445854444).
The spelling of 10315403143 in words is "ten billion, three hundred fifteen million, four hundred three thousand, one hundred forty-three".
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