Base | Representation |
---|---|
bin | 1001011000011011111111… |
… | …0000001000000000010010 |
3 | 1100112010221022002102121012 |
4 | 2112012333300020000102 |
5 | 2323002001441313100 |
6 | 33534502244330522 |
7 | 2113160026250126 |
oct | 226067760100022 |
9 | 40463838072535 |
10 | 10315433541650 |
11 | 3317829347616 |
12 | 11a72499a3a42 |
13 | 59a9835897a3 |
14 | 2793abcab586 |
15 | 12d4dc503135 |
hex | 961bfc08012 |
10315433541650 has 24 divisors (see below), whose sum is σ = 19366021410480. Its totient is φ = 4087611046160.
The previous prime is 10315433541649. The next prime is 10315433541689. The reversal of 10315433541650 is 5614533451301.
It is a junction number, because it is equal to n+sod(n) for n = 10315433541598 and 10315433541607.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 964053860 + ... + 964064559.
It is an arithmetic number, because the mean of its divisors is an integer number (806917558770).
Almost surely, 210315433541650 is an apocalyptic number.
10315433541650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
10315433541650 is a deficient number, since it is larger than the sum of its proper divisors (9050587868830).
10315433541650 is a wasteful number, since it uses less digits than its factorization.
10315433541650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1928118538 (or 1928118533 counting only the distinct ones).
The product of its (nonzero) digits is 324000, while the sum is 41.
Adding to 10315433541650 its reverse (5614533451301), we get a palindrome (15929966992951).
The spelling of 10315433541650 in words is "ten trillion, three hundred fifteen billion, four hundred thirty-three million, five hundred forty-one thousand, six hundred fifty".
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