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1032000113 = 1771984431
BaseRepresentation
bin111101100000110…
…001001001110001
32122220220001000102
4331200301021301
54103143000423
6250223202145
734400566454
oct7540611161
92586801012
101032000113
1148a59aa61
12249746355
13135a62671
149b0bb49b
1560902c28
hex3d831271

1032000113 has 8 divisors (see below), whose sum is σ = 1094238720. Its totient is φ = 969931840.

The previous prime is 1032000091. The next prime is 1032000121. The reversal of 1032000113 is 3110002301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1032000113 - 228 = 763564657 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1032000094 and 1032000103.

It is not an unprimeable number, because it can be changed into a prime (1032000163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29993 + ... + 54438.

It is an arithmetic number, because the mean of its divisors is an integer number (136779840).

Almost surely, 21032000113 is an apocalyptic number.

It is an amenable number.

1032000113 is a deficient number, since it is larger than the sum of its proper divisors (62238607).

1032000113 is an equidigital number, since it uses as much as digits as its factorization.

1032000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85167.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 1032000113 is about 32124.7585671862. The cubic root of 1032000113 is about 1010.5549063257.

Adding to 1032000113 its reverse (3110002301), we get a palindrome (4142002414).

The spelling of 1032000113 in words is "one billion, thirty-two million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 17 719 12223 84431 1435327 60705889 1032000113