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10320132003 = 33440044001
BaseRepresentation
bin10011001110010000…
…01011011110100011
3222122020011000200020
421213020023132203
5132113423211003
64424020124523
7513512450256
oct114710133643
928566130606
1010320132003
114416499a15
122000236743
13c861167ac
146dc89709d
15406046d53
hex26720b7a3

10320132003 has 4 divisors (see below), whose sum is σ = 13760176008. Its totient is φ = 6880088000.

The previous prime is 10320132001. The next prime is 10320132023. The reversal of 10320132003 is 30023102301.

10320132003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10320132003 - 21 = 10320132001 is a prime.

It is a super-3 number, since 3×103201320033 (a number of 31 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (10320132001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1720021998 + ... + 1720022003.

It is an arithmetic number, because the mean of its divisors is an integer number (3440044002).

Almost surely, 210320132003 is an apocalyptic number.

10320132003 is a deficient number, since it is larger than the sum of its proper divisors (3440044005).

10320132003 is an equidigital number, since it uses as much as digits as its factorization.

10320132003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3440044004.

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 10320132003 its reverse (30023102301), we get a palindrome (40343234304).

The spelling of 10320132003 in words is "ten billion, three hundred twenty million, one hundred thirty-two thousand, three".

Divisors: 1 3 3440044001 10320132003