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10320132023 is a prime number
BaseRepresentation
bin10011001110010000…
…01011011110110111
3222122020011000200222
421213020023132313
5132113423211043
64424020124555
7513512450315
oct114710133667
928566130628
1010320132023
114416499a33
12200023675b
13c861167c6
146dc8970b5
15406046d68
hex26720b7b7

10320132023 has 2 divisors, whose sum is σ = 10320132024. Its totient is φ = 10320132022.

The previous prime is 10320132001. The next prime is 10320132041. The reversal of 10320132023 is 32023102301.

It is a strong prime.

It is an emirp because it is prime and its reverse (32023102301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10320132023 - 212 = 10320127927 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10320131992 and 10320132010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10320132923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5160066011 + 5160066012.

It is an arithmetic number, because the mean of its divisors is an integer number (5160066012).

Almost surely, 210320132023 is an apocalyptic number.

10320132023 is a deficient number, since it is larger than the sum of its proper divisors (1).

10320132023 is an equidigital number, since it uses as much as digits as its factorization.

10320132023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 10320132023 its reverse (32023102301), we get a palindrome (42343234324).

The spelling of 10320132023 in words is "ten billion, three hundred twenty million, one hundred thirty-two thousand, twenty-three".