Base | Representation |
---|---|
bin | 10111011101110010110110… |
… | …011001001011111011010111 |
3 | 111112102001210001111102112011 |
4 | 113131302312121023323113 |
5 | 102011332242231302210 |
6 | 1003254331214005051 |
7 | 30511065002105101 |
oct | 2735626631137327 |
9 | 445361701442464 |
10 | 103202534244055 |
11 | 2a979a49107124 |
12 | b6a9413aa6787 |
13 | 4577c5a0240bc |
14 | 1b6b05a5d2571 |
15 | bde804bc9d8a |
hex | 5ddcb664bed7 |
103202534244055 has 8 divisors (see below), whose sum is σ = 123843472948944. Its totient is φ = 82561739491200.
The previous prime is 103202534244013. The next prime is 103202534244151. The reversal of 103202534244055 is 550442435202301.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 103202534244055 - 217 = 103202534112983 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 103202534243999 and 103202534244017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34404441 + ... + 37283650.
It is an arithmetic number, because the mean of its divisors is an integer number (15480434118618).
Almost surely, 2103202534244055 is an apocalyptic number.
103202534244055 is a deficient number, since it is larger than the sum of its proper divisors (20640938704889).
103202534244055 is an equidigital number, since it uses as much as digits as its factorization.
103202534244055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71976017.
The product of its (nonzero) digits is 576000, while the sum is 40.
Adding to 103202534244055 its reverse (550442435202301), we get a palindrome (653644969446356).
The spelling of 103202534244055 in words is "one hundred three trillion, two hundred two billion, five hundred thirty-four million, two hundred forty-four thousand, fifty-five".
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