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10320303113 = 23448708831
BaseRepresentation
bin10011001110010001…
…10101010000001001
3222122020110201101122
421213020311100021
5132113444144423
64424023525025
7513514062161
oct114710652011
928566421348
1010320303113
1144165a652a
1220002b9775
13c86176643
146dc8dd5a1
1540607c8c8
hex267235409

10320303113 has 4 divisors (see below), whose sum is σ = 10769011968. Its totient is φ = 9871594260.

The previous prime is 10320303061. The next prime is 10320303137. The reversal of 10320303113 is 31130302301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10320303113 - 226 = 10253194249 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10320303091 and 10320303100.

It is not an unprimeable number, because it can be changed into a prime (10320303173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224354393 + ... + 224354438.

It is an arithmetic number, because the mean of its divisors is an integer number (2692252992).

Almost surely, 210320303113 is an apocalyptic number.

It is an amenable number.

10320303113 is a deficient number, since it is larger than the sum of its proper divisors (448708855).

10320303113 is an equidigital number, since it uses as much as digits as its factorization.

10320303113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 448708854.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 10320303113 its reverse (31130302301), we get a palindrome (41450605414).

The spelling of 10320303113 in words is "ten billion, three hundred twenty million, three hundred three thousand, one hundred thirteen".

Divisors: 1 23 448708831 10320303113