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10322100213 = 33440700071
BaseRepresentation
bin10011001110011111…
…01011111111110101
3222122100212000112220
421213033223333311
5132114424201323
64424130232553
7513535255425
oct114717537765
928570760486
1010322100213
114417613737
122000a25759
13c86655609
146dcc4a485
154062d50e3
hex2673ebff5

10322100213 has 4 divisors (see below), whose sum is σ = 13762800288. Its totient is φ = 6881400140.

The previous prime is 10322100211. The next prime is 10322100221. The reversal of 10322100213 is 31200122301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10322100213 - 21 = 10322100211 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10322100192 and 10322100201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10322100211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1720350033 + ... + 1720350038.

It is an arithmetic number, because the mean of its divisors is an integer number (3440700072).

Almost surely, 210322100213 is an apocalyptic number.

It is an amenable number.

10322100213 is a deficient number, since it is larger than the sum of its proper divisors (3440700075).

10322100213 is an equidigital number, since it uses as much as digits as its factorization.

10322100213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3440700074.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 10322100213 its reverse (31200122301), we get a palindrome (41522222514).

The spelling of 10322100213 in words is "ten billion, three hundred twenty-two million, one hundred thousand, two hundred thirteen".

Divisors: 1 3 3440700071 10322100213