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10322147135 = 52064429427
BaseRepresentation
bin10011001110011111…
…10111011100111111
3222122100221101220202
421213033313130333
5132114432202020
64424131234115
7513535542266
oct114717673477
928570841822
1010322147135
114417645a13
122000a4893b
13c86670a91
146dcc5d5dd
154062e3e75
hex2673f773f

10322147135 has 4 divisors (see below), whose sum is σ = 12386576568. Its totient is φ = 8257717704.

The previous prime is 10322147117. The next prime is 10322147153. The reversal of 10322147135 is 53174122301.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (10322147117) and next prime (10322147153).

It is a cyclic number.

It is not a de Polignac number, because 10322147135 - 26 = 10322147071 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10322147098 and 10322147107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1032214709 + ... + 1032214718.

It is an arithmetic number, because the mean of its divisors is an integer number (3096644142).

Almost surely, 210322147135 is an apocalyptic number.

10322147135 is a deficient number, since it is larger than the sum of its proper divisors (2064429433).

10322147135 is an equidigital number, since it uses as much as digits as its factorization.

10322147135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2064429432.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 10322147135 its reverse (53174122301), we get a palindrome (63496269436).

The spelling of 10322147135 in words is "ten billion, three hundred twenty-two million, one hundred forty-seven thousand, one hundred thirty-five".

Divisors: 1 5 2064429427 10322147135