Base | Representation |
---|---|
bin | 11110000010110111011… |
… | …10001111110101111101 |
3 | 10122200121220220110101102 |
4 | 33001123232033311331 |
5 | 113403203214014323 |
6 | 2110125112022445 |
7 | 134404060504541 |
oct | 17013356176575 |
9 | 3580556813342 |
10 | 1032331001213 |
11 | 368899a34706 |
12 | 1480a5691a25 |
13 | 7646b56b6a5 |
14 | 37d722ada21 |
15 | 1bcbed37328 |
hex | f05bb8fd7d |
1032331001213 has 4 divisors (see below), whose sum is σ = 1032798756480. Its totient is φ = 1031863245948.
The previous prime is 1032331001183. The next prime is 1032331001249. The reversal of 1032331001213 is 3121001332301.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1032331001213 - 214 = 1032330984829 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1032331001263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233874323 + ... + 233878736.
It is an arithmetic number, because the mean of its divisors is an integer number (258199689120).
Almost surely, 21032331001213 is an apocalyptic number.
It is an amenable number.
1032331001213 is a deficient number, since it is larger than the sum of its proper divisors (467755267).
1032331001213 is an equidigital number, since it uses as much as digits as its factorization.
1032331001213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 467755266.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1032331001213 its reverse (3121001332301), we get a palindrome (4153332333514).
The spelling of 1032331001213 in words is "one trillion, thirty-two billion, three hundred thirty-one million, one thousand, two hundred thirteen".
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