Base | Representation |
---|---|
bin | 1001011000111111101000… |
… | …1101110100111101101101 |
3 | 1100120001122022020102020221 |
4 | 2112033322031310331231 |
5 | 2323131102102403401 |
6 | 33543124100011341 |
7 | 2113646142561412 |
oct | 226177215647555 |
9 | 40501568212227 |
10 | 10325004341101 |
11 | 332089a86192a |
12 | 11a907b090b51 |
13 | 59b84a380528 |
14 | 279a39028109 |
15 | 12d89c8807a1 |
hex | 963fa374f6d |
10325004341101 has 2 divisors, whose sum is σ = 10325004341102. Its totient is φ = 10325004341100.
The previous prime is 10325004341089. The next prime is 10325004341117. The reversal of 10325004341101 is 10114340052301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8229588863076 + 2095415478025 = 2868726^2 + 1447555^2 .
It is an emirp because it is prime and its reverse (10114340052301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10325004341101 - 221 = 10325002243949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10325004344101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5162502170550 + 5162502170551.
It is an arithmetic number, because the mean of its divisors is an integer number (5162502170551).
Almost surely, 210325004341101 is an apocalyptic number.
It is an amenable number.
10325004341101 is a deficient number, since it is larger than the sum of its proper divisors (1).
10325004341101 is an equidigital number, since it uses as much as digits as its factorization.
10325004341101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 10325004341101 its reverse (10114340052301), we get a palindrome (20439344393402).
The spelling of 10325004341101 in words is "ten trillion, three hundred twenty-five billion, four million, three hundred forty-one thousand, one hundred one".
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