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10325004341101 is a prime number
BaseRepresentation
bin1001011000111111101000…
…1101110100111101101101
31100120001122022020102020221
42112033322031310331231
52323131102102403401
633543124100011341
72113646142561412
oct226177215647555
940501568212227
1010325004341101
11332089a86192a
1211a907b090b51
1359b84a380528
14279a39028109
1512d89c8807a1
hex963fa374f6d

10325004341101 has 2 divisors, whose sum is σ = 10325004341102. Its totient is φ = 10325004341100.

The previous prime is 10325004341089. The next prime is 10325004341117. The reversal of 10325004341101 is 10114340052301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8229588863076 + 2095415478025 = 2868726^2 + 1447555^2 .

It is an emirp because it is prime and its reverse (10114340052301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10325004341101 - 221 = 10325002243949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10325004344101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5162502170550 + 5162502170551.

It is an arithmetic number, because the mean of its divisors is an integer number (5162502170551).

Almost surely, 210325004341101 is an apocalyptic number.

It is an amenable number.

10325004341101 is a deficient number, since it is larger than the sum of its proper divisors (1).

10325004341101 is an equidigital number, since it uses as much as digits as its factorization.

10325004341101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 10325004341101 its reverse (10114340052301), we get a palindrome (20439344393402).

The spelling of 10325004341101 in words is "ten trillion, three hundred twenty-five billion, four million, three hundred forty-one thousand, one hundred one".