Base | Representation |
---|---|
bin | 1001011000111111101000… |
… | …1101110100111101111101 |
3 | 1100120001122022020102021112 |
4 | 2112033322031310331331 |
5 | 2323131102102403432 |
6 | 33543124100011405 |
7 | 2113646142561434 |
oct | 226177215647575 |
9 | 40501568212245 |
10 | 10325004341117 |
11 | 332089a861944 |
12 | 11a907b090b65 |
13 | 59b84a38053b |
14 | 279a3902811b |
15 | 12d89c8807b2 |
hex | 963fa374f7d |
10325004341117 has 2 divisors, whose sum is σ = 10325004341118. Its totient is φ = 10325004341116.
The previous prime is 10325004341101. The next prime is 10325004341123. The reversal of 10325004341117 is 71114340052301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9934971616441 + 390032724676 = 3151979^2 + 624526^2 .
It is a cyclic number.
It is not a de Polignac number, because 10325004341117 - 24 = 10325004341101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10325004341317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5162502170558 + 5162502170559.
It is an arithmetic number, because the mean of its divisors is an integer number (5162502170559).
Almost surely, 210325004341117 is an apocalyptic number.
It is an amenable number.
10325004341117 is a deficient number, since it is larger than the sum of its proper divisors (1).
10325004341117 is an equidigital number, since it uses as much as digits as its factorization.
10325004341117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 10325004341117 its reverse (71114340052301), we get a palindrome (81439344393418).
The spelling of 10325004341117 in words is "ten trillion, three hundred twenty-five billion, four million, three hundred forty-one thousand, one hundred seventeen".
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