Base | Representation |
---|---|
bin | 10011001110110110… |
… | …01001001000001001 |
3 | 222122120111120202102 |
4 | 21213123021020021 |
5 | 132121211244423 |
6 | 4424314443145 |
7 | 513602633303 |
oct | 114733111011 |
9 | 28576446672 |
10 | 10325103113 |
11 | 4419284876 |
12 | 2001a334b5 |
13 | c87167390 |
14 | 6dd3cc973 |
15 | 4066c9c28 |
hex | 2676c9209 |
10325103113 has 8 divisors (see below), whose sum is σ = 11138101128. Its totient is φ = 9514785024.
The previous prime is 10325103097. The next prime is 10325103149. The reversal of 10325103113 is 31130152301.
It can be written as a sum of positive squares in 4 ways, for example, as 81234169 + 10243868944 = 9013^2 + 101212^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10325103113 - 24 = 10325103097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10325103193) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 661970 + ... + 677387.
It is an arithmetic number, because the mean of its divisors is an integer number (1392262641).
Almost surely, 210325103113 is an apocalyptic number.
10325103113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10325103113 is a deficient number, since it is larger than the sum of its proper divisors (812998015).
10325103113 is a wasteful number, since it uses less digits than its factorization.
10325103113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1339963.
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 10325103113 its reverse (31130152301), we get a palindrome (41455255414).
The spelling of 10325103113 in words is "ten billion, three hundred twenty-five million, one hundred three thousand, one hundred thirteen".
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