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103301113030 = 2575133137491
BaseRepresentation
bin110000000110100111…
…0011110010011000110
3100212122020021021000021
41200031032132103012
53143030041104110
6115242245205354
710314616654513
oct1401516362306
9325566237007
10103301113030
113a89a870195
121802b40085a
1399836c156b
144ddd64a30a
152a48e5c2da
hex180d39e4c6

103301113030 has 16 divisors (see below), whose sum is σ = 185945830704. Its totient is φ = 41319594720.

The previous prime is 103301112989. The next prime is 103301113067. The reversal of 103301113030 is 30311103301.

It is a super-2 number, since 2×1033011130302 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103301112995 and 103301113013.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 682585 + ... + 820075.

It is an arithmetic number, because the mean of its divisors is an integer number (11621614419).

Almost surely, 2103301113030 is an apocalyptic number.

103301113030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

103301113030 is a deficient number, since it is larger than the sum of its proper divisors (82644717674).

103301113030 is a wasteful number, since it uses less digits than its factorization.

103301113030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 212631.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 103301113030 its reverse (30311103301), we get a palindrome (133612216331).

The spelling of 103301113030 in words is "one hundred three billion, three hundred one million, one hundred thirteen thousand, thirty".

Divisors: 1 2 5 10 75133 137491 150266 274982 375665 687455 751330 1374910 10330111303 20660222606 51650556515 103301113030