Base | Representation |
---|---|
bin | 10111011111001110110001… |
… | …000111101010101010111111 |
3 | 111112202111112022222222021101 |
4 | 113133032301013222222333 |
5 | 102014441404340404434 |
6 | 1003411532510513531 |
7 | 30521160531232045 |
oct | 2737166107525277 |
9 | 445674468888241 |
10 | 103301230013119 |
11 | 2aa07895315216 |
12 | b704578b058a7 |
13 | 4584358576b58 |
14 | 1b71b40350395 |
15 | be217e68ab14 |
hex | 5df3b11eaabf |
103301230013119 has 2 divisors, whose sum is σ = 103301230013120. Its totient is φ = 103301230013118.
The previous prime is 103301230013117. The next prime is 103301230013159. The reversal of 103301230013119 is 911310032103301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103301230013119 - 21 = 103301230013117 is a prime.
It is a super-4 number, since 4×1033012300131194 (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
Together with 103301230013117, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103301230013117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51650615006559 + 51650615006560.
It is an arithmetic number, because the mean of its divisors is an integer number (51650615006560).
Almost surely, 2103301230013119 is an apocalyptic number.
103301230013119 is a deficient number, since it is larger than the sum of its proper divisors (1).
103301230013119 is an equidigital number, since it uses as much as digits as its factorization.
103301230013119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 103301230013119 in words is "one hundred three trillion, three hundred one billion, two hundred thirty million, thirteen thousand, one hundred nineteen".
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